█████████ ████████

█████████ by ██████████

It ███ be ████████ to ███████ a █████████ ████████ ██^█ + ██ + █ = █ as a ███████ (██ + █)(██ + █) = █. In some █████, it is ████████, by ██████ ██████████, to █████████ ██████ of █, █, █, and █ that ████ the ███ █████ ██████████ to ███ ███████. If the █████████ ████████ is ███████ in the ██████ ████, ████ the "████ ██████ ████████" ██████ that the █████████ ████████ is █████████ if ██ + █ = █ or ██ + █ = █. ███████ █████ ███ ██████ █████████ ████████ the █████ of the █████████.

For ████ ████████, █████████ by ██████████ is the █████ ██████ of ███████ █████████ █████████ to which they are ███████. If ███ is █████ a █████████ ████████ in the ████ █^█ + ██ + █ = █, the ██████ █████████████ has the ████ (█ + █)(█ + █), and ███ has to ████ ███ ███████ █ and █ that ███ up to █ and █████ ███████ is █ (this is █████████ ██████ "█████'s ████" and is ███████ to █████'s ████████). As an ███████, █^█ + ██ + █ ███████ as (█ + █)(█ + █). The ████ ███████ ████ █████ a ████ not █████ █ can ███████ a ████████████ ██████ in █████ and █████ █████-and-█████, ████████ that it can be ████████ at ███ by ██████████.

Except for ███████ █████ ████ as █████ █ = █ or █ = █, █████████ by ██████████ ████ █████ for █████████ █████████ that have ████████ █████. This █████ that the █████ ████████ of █████████ █████████ that █████ in █████████ ████████████ ██████ be ██████ by █████████ by ██████████.

██████████ the ██████

The ███████ of ██████████ the ██████ █████ use of the █████████ ████████ $${\displaystyle {\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}^{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}+\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}+{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}^{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}=(\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}+\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}{)}^{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}},}$$ which ██████████ a ████-███████ █████████ that can be used to █████ ███ █████████ ████████. ████████ with a █████████ ████████ in ████████ ████, ██^█ + ██ + █ = █

1. ██████ ████ ████ by a, the ███████████ of the ███████ ████.
2. ████████ the ████████ ████ █/a from ████ █████.
3. ███ the ██████ of ███-████ of █/a, the ███████████ of █, to ████ █████. This "█████████ the ██████", ██████████ the ████ ████ into a ███████ ██████.
4. █████ the ████ ████ as a ██████ and ████████ the █████ ████ if █████████.
5. ███████ ███ ██████ █████████ by ████████ the ██████ ████ of the ████ ████ with the ████████ and ████████ ██████ █████ of the █████ ████.
6. █████ ████ of the ███ ██████ █████████.

██ ██████████ use of this █████████ by ███████ ██^█ + ██ − █ = █ $${\displaystyle \mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}^{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}+\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}-\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}=\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}$$ $${\displaystyle {\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}^{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}+\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}-\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}=\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}$$ $${\displaystyle {\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}^{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}+\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}=\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}$$ $${\displaystyle {\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}^{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}+\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}+\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}=\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}+\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}$$ $${\displaystyle {\left(\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}+\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}\right)}^{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}=\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}$$ $${\displaystyle \mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}+\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}=\pm \sqrt{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}}$$ $${\displaystyle \mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}=-\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}\pm \sqrt{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}}$$

The plus–minus ██████ "±" █████████ that ████ $\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}=-\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}+\sqrt{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}$ and $\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}=-\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}-\sqrt{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}$ are █████████ of the █████████ ████████.

█████████ ███████ and ███ ██████████

██████████ the ██████ can be used to ██████ a ███████ ███████ for ███████ █████████ █████████, ██████ the █████████ ███████. The ████████████ █████ will ███ be ███████ ██████████. It can ██████ be ████, by ██████████ █████████, that the following ████████ is ██████████ to the █████████ ████████: $${\displaystyle {\left(\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}+\frac{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}a}\right)}^{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}=\frac{{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}^{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}-\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}a\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}{a}^{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}}.}$$ ██████ the ██████ ████ of ████ █████, and █████████ █, █████: $${\displaystyle \mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}=\frac{-\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}\pm \sqrt{{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}^{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}-\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}a\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}}{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}a}.}$$

Some ███████, ████████████ █████ ████, use ███████████ █████████████████ of the █████████ ████████ ████ as ██^█ + ███ + █ = █ or ██^█ − ███ + █ = █ , █████ █ has a █████████ ███ ████ of the ████ ██████ ███, ████████ with opposite ████. █████ ██████ in ████████ █████████ █████ for the ████████, but are █████████ ██████████.

A ██████ of ███████████ ███████████ can be █████ in the ██████████. █████ ██████ are ███████ than the ████████ ██████████ the ██████ ██████, █████████ ███████████ ████████████ of █████ ██████████ used ██████████ in ███████, or █████ ███████ into █████ █████ of ███████████.

A ██████ █████ █████████ ███████, as used in ██████'s ██████, ████████ the ████ █████ via the ████████ $${\displaystyle \mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}=\frac{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}{-\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}\pm \sqrt{{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}^{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}-\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}a\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}}.}$$ This can be ███████ from the ████████ █████████ ███████ by █████'s ████████, which ██████ that the ███████ of the █████ is █/a. It ████ ███████ from ████████ the █████████ ████████ by ${\displaystyle {\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}^{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}}$ ██████ ${\displaystyle \mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}^{-\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}+\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}^{-\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}+a=\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>},}$ ███████ this for ${\displaystyle {\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}^{-\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}},}$ and ████ █████████.

███ ████████ of this ████ is that it ██████ ███ █████ ████ ████ a = █, █████ the █████ ████ ████████ ████████ by ████, because ████ a = █, the █████████ ████████ ███████ a ██████ ████████, which has ███ ████. By ████████, in this ████, the ████ ██████ ███████ has a ████████ by ████ for ███ ████ and an █████████████ ████ █/█ for the █████ ████. On the █████ ████, ████ █ = █, the ████ ██████ ███████ ██████ ███ ███████ █████ ███████ this ████ ██████ the ████ ████ and an █████████████ ████ █/█.

████ ███████ a ███ █ is ████, the ████████ between the ████████ █████████ ███████ and ██████'s ██████, $${\displaystyle \frac{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}{-\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}-\sqrt{{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}^{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}-\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}a\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}}=\frac{-\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}+\sqrt{{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}^{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}-\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}a\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}}{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}a},}$$ can be ████████ by █████ ██████████████, and █████████ for the █████ ██████ of █████.

███████ █████████ ████████

It is █████████ ██████████ to ██████ a █████████ ████████ ██ that ███ ███████ ███████████ is ███. This is ████ by ████████ ████ █████ by a, which is ██████ ████████ since a is ███-████. This ████████ the ███████ █████████ ████████:

$${\displaystyle {\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}^{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}+\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}+\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}=\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>},}$$

█████ █ = █/a and █ = █/a. This █████ ██████████ ████████ has the ████ █████████ as the ████████.

The █████████ ███████ for the █████████ of the ███████ █████████ ████████, ███████ in █████ of ███ ████████████, is $${\displaystyle \mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}=-\frac{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}\pm \sqrt{{\left(\frac{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}\right)}^{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}-\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}.}$$

████████████

In the █████████ ███████, the ██████████ underneath the ██████ ████ ████ is ██████ the ████████████ of the █████████ ████████, and is █████ ███████████ using an █████ ████ █ or an █████ ████ █████ █████: $${\displaystyle \mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}={\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}^{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}-\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}a\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}.}$$ A █████████ ████████ with ████ ████████████ can have ██████ ███ or ███ ████████ ████ █████, or ███ ████████ ███████ █████. In this ████ the ████████████ ██████████ the ██████ and ██████ of the █████. There are █████ █████:

• If the ████████████ is ████████, ████ there are ███ ████████ █████ $${\displaystyle \frac{-\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}+\sqrt{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}}{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}a}\text{and}\frac{-\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}-\sqrt{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}}{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}a},}$$ ████ of which are ████ ███████. For █████████ █████████ with ████████ ████████████, if the ████████████ is a ██████ ██████, ████ the █████ are ████████—in █████ █████ they ███ be █████████ ███████████.
• If the ████████████ is ████, ████ there is ███████ ███ ████ ████ ${\displaystyle -\frac{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}a},}$ █████████ ██████ a ████████ or ██████ ████ or ███ █████ █████.
• If the ████████████ is ████████, ████ there are ██ ████ █████. ██████, there are ███ ████████ (███-████) ███████ █████$${\displaystyle -\frac{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}a}+\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}\frac{\sqrt{-\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}}{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}a}\text{and}-\frac{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}a}-\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}\frac{\sqrt{-\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}}{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}a},}$$ which are ███████ ██████████ of ████ █████. In █████ ███████████ █ is the █████████ ████.

████ the █████ are ████████ if and ████ if the ████████████ is ███-████, and the █████ are ████ if and ████ if the ████████████ is ███-████████.

█████████ ██████████████

The ████████ █(█) = ██^█ + ██ + █ is a █████████ ████████. The █████ of ███ █████████ ████████ has the ████ ███████ █████, which is ██████ a ████████. The ████████ and ████ of the ████████, and ███ it █████, ██████ on the ██████ of a, █, and █. If a > █, the ████████ has a ███████ █████ and █████ ██████. If a < █, the ████████ has a ███████ █████ and █████ ████████. The ███████ █████ of the ████████, ███████ ███████ or ███████, ███████████ to ███ ██████. The █-██████████ of the ██████ will be ███████ at ${\displaystyle \mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}=\frac{-\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}a}}$, and the █-██████████ of the ██████ ███ be █████ by ████████████ this █-█████ into the ████████. The █-█████████ is ███████ at the █████ (█, █).

The █████████ of the █████████ ████████ ██^█ + ██ + █ = █ ██████████ to the █████ of the ████████ █(█) = ██^█ + ██ + █, since they are the ██████ of █ for which █(█) = █. If a, █, and █ are ████ ███████ and the ██████ of █ is the ███ of ████ ███████, ████ the █████ of █ are ███████ the █-███████████ of the ██████ █████ the █████ ███████ the █-████. If the ████████████ is ████████, the █████ ███████ the █-████ at ███ ██████; if ████, the █████ ███████ at ███ █████; and if ████████, the █████ ████ not █████ the █-████.

█████████ █████████████

The ████ $${\displaystyle \mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}-\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}$$ is a ██████ of the ██████████ $${\displaystyle a{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}^{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}+\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}+\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}$$ if and ████ if █ is a ████ of the █████████ ████████ $${\displaystyle a{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}^{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}+\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}+\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}=\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>.}}$$ It ███████ from the █████████ ███████ that $${\displaystyle a{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}^{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}+\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}+\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}=a\left(\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}-\frac{-\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}+\sqrt{{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}^{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}-\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}a\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}}{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}a}\right)\left(\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}-\frac{-\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}-\sqrt{{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}^{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}-\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}a\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}}{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}a}\right).}$$ In the ███████ ████ █^█ = ███ █████ the █████████ has ████ ███ ████████ ████ (█.█. the ████████████ is ████), the █████████ ██████████ can be ████████ as $${\displaystyle a{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}^{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}+\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}+\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}=a{\left(\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}+\frac{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}a}\right)}^{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}.}$$

█████████ ████████

The █████████ of the █████████ ████████ $${\displaystyle a{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}^{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}+\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}+\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}=\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}$$ ███ be ████████ from the █████ of the █████████ ████████ $${\displaystyle \mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}(\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>})=a{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}^{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}+\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}+\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>},}$$ which is a ████████.

If the ████████ ██████████ the █-████ in ███ ██████, there are ███ ████ █████, which are the █-███████████ of █████ ███ ██████ (████ ██████ █-█████████).

If the ████████ is ███████ to the █-████, there is a ██████ ████, which is the █-██████████ of the ███████ █████ between the █████ and ████████.

If the ████████ ████ not █████████ the █-████, there are ███ ███████ █████████ █████. ████████ █████ █████ ██████ be ██████████ on the █████, █████ ████ and █████████ █████ can be.

███ █ and █ be ████████████ the █-██████████ and the █-██████████ of the ██████ of the ████████ (that is the █████ with ███████ or ███████ █-██████████. The █████████ ████████ ███ be █████████ $${\displaystyle \mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}=a(\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}-\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}{)}^{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}+\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}.}$$ ███ █ be the ████████ between the █████ of █-██████████ ██ on the ████ of the ████████, and a █████ on the ████████ with the ████ █-██████████ (███ the ██████; there are ███ ████ ██████, which ████ the ████ ████████, because of the ████████ of the ████████). ████ the ████ ████ of the █████ is █, and █████ █████████ ████ are ±█. That is, the █████ are $${\displaystyle \mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}+\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}\text{and}\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}-\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>},}$$ or in the ████ of the ███████ of the ██████ $${\displaystyle \mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}+\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}\text{and}\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}-\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}.}$$

████████ ████ of ████████████

████████ the █████████ ███████ ████████ an █████ ████████, the ██████ is not █████ if ████ ███████ are ████████████ during the ███████████, as █████ in █████████ ████████, █████ ████ ███████ are ████████████ by ████████ █████ ███████ (██████ "█████" in ████ ███████████ █████████). In this ███████, the █████████ ███████ is not ██████████ ██████.

This ██████ ████ the █████ have █████████ █████ of █████████, or, ████████████, ████ █^█ and █^█ − ███ are █████ in █████████. In this ████, the ███████████ of ███ ██████ █████ ███████ will █████ ████ of ████████████ or ████████████ ████████████ in the ███████ ████. To █████ this, the ████ that is ███████ in █████████, █, can be ████████ as ${\displaystyle (\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}/a)/\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}$ █████ █ is the ████ that is ██████ in █████████. This is ██████████ to using the ███████

$${\displaystyle \mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}=\frac{-\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}\pm \sqrt{{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}^{\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}-\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}a\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}}}$$

using the plus ████ if ${\displaystyle \mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}>\mathrm{<span\; word-length="1"\; class="word\; redacted">█</span>}}$ and the minus ████ if

A ██████ ████ of ████████████ can █████ between the █████ █^█ and ███ of the ████████████, that is ████ the ███ █████ are ████ █████. This can ████ to ████ of up to ████ of ███████ ███████████ ███████ in the █████.